11x^2-16x-16=0

Solution for 11x^2-16x-16=0 equation:

11x^2-16x-16=0

a = 11; b = -16; c = -16;
Δ = b2-4ac
Δ = -162-4·11·(-16)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{15}}{2*11}=\frac{16-8\sqrt{15}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{15}}{2*11}=\frac{16+8\sqrt{15}}{22}
$